Question

The number of visitors, V, a website receives doubles every 3 months. If 6 months ago the website received 24,500 visitors, how many visitors, in thousands, will it receive t years from now?

Answer 1

i believe its V=24.5(2 )

Answer 2

Answer:
`y=98(2)^(4t)`

Explanation:

The exponential growth function is given by :_

`y=A(b)^x`, where A is the initial amount , b is the multiplicative growth rate and x is the time period.

Given : The number of visitors, V, a website receives doubles every 3 months.

i.e. The growth factor for every 3 months : b= 2

For 6 months , the number of time period =
`x=(6)/(3)=2`

If 6 months ago the website received 24,500 visitors, then the number of visitors now :-

`y=24500(2)^2=98000`

Time periods for 1 year =
`(12)/(3)=4`

Then, time periods for increase in t-years=
`4t`

For now, the initial number of visitors ( in thousand)=
`A_1=98`

Then, the function of the number of visitors (in thousand) website receive in t years:-

`y=98(2)^(4t)`