Question

Factor 6m^2+25mn+11n^2 and if you can please tell me a step-by-step explanation, please! Thanks

Answer 1

Answer:
`(2m+n)(3m+11n)`

Step-by-step explanation:

`a(x-(-b-√(b^2-4ac) )/(2a) )`

`a(x+(-b-√(b^2-4ac) )/(2a) )`

`6(m-(-25n+√((25n)^2-4*6*11n^2) )/(2*6) )`
`6(m+(-25n+√((25n)^2-4*6*11n^2) )/(2*6) )`

`(2m+n)(3m+11n)`

Answer 2

(3m+11n)(2m+n)

Explanation:

We have given a expression.

6m²+25mn+11n²

We have to factorize above expression.

Splitting the middle term of above expression so that the sum of two terms should be 25 and their product be 66.

6m²+22mn+3mn+11n²

Making groups, we have

2m(3m+11n)+n(3m+11n)

Taking 3m+11n as common, we have

(3m+11n)(2m+n) which is the answer.