Answer:
Explanation:
Let the number of nickels be n and dimes be d.
Consider:
- n = 5¢, d = 10¢, $8 = 800¢
We have equations below:
- d + n = 105
- 10d + 5n = 800
Multiply the first equation by 10 and subtract the second equation to eliminate d and solve for n:
- 10d + 10n - 10d - 5n = 1050 - 800
- 5n = 250
- n = 50
He has 50 nickels