Answer:
The equation represent a circle with center at the origin and radius 6 units
Explanation:
we know that
The equation of a circle in center radius form is equal to

where
(h,k) is the center of the circle
r is the radius of the circle
In this problem we have

so
the center of the circle is the origin

and the radius is

therefore
The equation represent a circle with center at the origin and radius 6 units