Question

The circle below is centered at the point (4, 1) and has a radius of length 2 What is its equation?

Answer 1

(x - 4)^2 + (y - 1)^2 = 2^2 = 4

Explanation:

The applicable equation of a circle with center at (h, k) and radius r is

(x - h)^2 + (y - k)^2 = r^2. Here, h = 4; k = 1; and r = 2.

So the desired equation is (x - 4)^2 + (y - 1)^2 = 2^2