Question

Please help im no good at math especially not this math

Answer 1

Could you elaborate on the details?

Answer 2

`\bigtriangleup ABD \cong \bigtriangleup BCD\Rightarrow (CD)/(BD) = (BD)/(AD) \Leftrightarrow CD = x = \frac{ {BD}^(2) }{AD} = \frac{ {8}^(2) }{15} = (64)/(15) \\ BC =y = \sqrt{ {BD}^(2) + {CD}^(2) } = \sqrt{ { {8}^(2) +(64)/(15) }^(2) } = (136)/(15) \\ \Rightarrow x = (64)/(15) , \: y = (136)/(15)`