Question

a gas in a container with a fixed volume was originally at a pressure of 317kpa and a temperature of 154k. what is the new pressure in atm if the temperature is increased to 235k​

Answer 1

Hello!

The answer is: 4.77atm

Why?

Since there's a fixed volume, we can use the the Gay-Lussac's Law which stablish a relation between the pressure and the temperature:

`(P)/(T)=k`

P is the volume of the gas

t is the temperature of the gas

k is the proportionality constant

We also have the following equation:

`(P1)/(T1)=(P2)/(T2)`

Where:

`P2=(P1*T2)/(T1)=(317kPa*235K)/(154K)=483.73kPa`

We are asked to find the pressure in atm, so we must convert 483.73kPa to atm:

`1kPa=0.009869atm`

Then,

`483.733kPa*(0.009869atm)/(1kPa)=4.77atm`

Have a nice day!