Question

The following reaction occurs in a car’s catalytic converter.

2NO(g) + 2CO(g) ==> N2(g) + 2CO2(g)
Which answer best describes the reducing and oxidizing processes in this reaction?
NO and CO are both reducing agents.
NO and CO are both oxidizing agents.
The oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.
The oxidation state of nitrogen in NO changes from 0 to +2, and the oxidation state of carbon in CO changes from +4 to +2 as the reaction proceeds.

Answer 1

C

Step-by-step explanation:

Edge

Answer 2

Answer:The correct answer is ;

The oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

Step-by-step explanation:

`2NO(g)+2CO(g)\rightarrow N_2(g)+2CO_2(g)`

In an oxidation recation addition of oxygen atom takes place or loss of electrons takes place.

In an reduction reaction removal of oxygen atom takes place or gain of electrons takes place.

In the given reaction , the nitrogen atom is present in +2 oxidation state in NO molecule and present in 0 oxidation state in
`N_2` molecule. Hence, nitrogen is getting reduced that is reduction reaction. NO is oxidizing agent

In the given reaction , the carbon atom is present in +2 oxidation state in CO molecule and present in +4 oxidation state in
`CO_2` molecule. Hence ,carbon is getting oxidized that is oxidation reaction. CO is a reducing agent.