Question

A gas has a volume of 25.6 L at a temperature of 278 K. What will be the new temperature, in C, if

the pressure is kept constant and the volume is decreased to 16.2 L?​

Answer 1

Hello!

The answer is: -97.37° C

Why?

According to the Charles and Gay-Lussac's Law we have that:

`(V)/(T)=k`

Where:

v is the volume of the gas

t is the temperature of the gas

k is the proportionality constant

From the Gay-Lussac's Law we also have the following relation:

`(V1)/(T1)=(V2)/(T2)`

Since we need to find the new temperature (T2) we can use the last equation:

`(V1)/(T1)=(V2)/(T2)\\\\T2=(V2*T1)/(V1)=(16.2L*278K)/(25.6L)=175.92K`

We are asked to find the temperature in Celsius degrees, so, we must convert the result (in K) to Celsius degrees:

`Celsius=K-273.15=175.92-273.15=-97.37`

So, the temperature is -97.37° C

Have a nice day!