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If the quadratic formula is used to solve 2x2 = 8x -3, what are the solutions

2 Answers

5 votes

Answer:

2x2 = 8x-3

4 = 8x - 3 | +3

7=8x

x=7/8

Explanation:

User Kooskoos
by
7.9k points
3 votes

Answer:

x = 2 ±
(1)/(2)
√(10)

Explanation:

Given a quadratic equation in standard form : ax² + bx + c = 0

Then we can solve for x using the quadratic formula

Given

2x² = 8x - 3 ( subtract 8x - 3 from both sides )

2x² - 8x + 3 = 0 ← in standard form

with a = 2, b = - 8 and c = 3, hence

x = (- (- 8) ±
√((-8)^2-(4(2)(3))) / 4

= (8 ±
√(64-24)) / 4

= (8 ±
√(40)) / 4

= (8 ± 2
√(10) ) / 4

=
(8)/(4) ±
(2√(10) )/(4)

= 2 ±
(1)/(2)
√(10)

User Vincent Durmont
by
7.8k points

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