Answer:
Solution,
since the factor of f(p) = p-1
we know, f(p)= 0
p=1 (from remainder theorem)
now,
f(p) =p^4+p^2+p-k
0= 1^4+1^2+1-k
0= 1+1+1-k
0= 3-k
k=3
Answer: k = 3
because p - 1 is a factor of the equation
=> at p = 1, p^4 + p² + p - k =0
with p =1, we have: 1 + 1 + 1 - k = 0
⇔ k = 3
Explanation:
3.5m questions
4.5m answers