Question

An empty coke bottle is dropped off a 236 m high cliff in Nairobi. At what speed does the bottle hit the ground?

Answer 1

v=68[m/s]

Step-by-step explanation:

To solve this problem we have to use the law of energy conservation, which tells us that potential energy is converted into kinetic energy.

`E_(pot)=E_(kin)`

`E_(pot)=m*g*h`

`E_(kin)=0.5*m*v^(2)`

where:

m = mass [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 236 [m]

v = velocity [m/s]

`m*9.81*236=0.5*m*v^(2)\\2315.16 = 0.5*v^(2)\\v=√(4630.32) \\v=68[m/s]`