1. Answer:
From the graph, we can see that when
, then
. On the other hand, we need to calculate
, that is, the output of
at
, so
. Well, we have two values:
![g(-1)=-3 \\ \\ h(-1)=11](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vuv43fuinmnlwbiazaccg7lih7o3bc0sz8.png)
For
the options are:
a) is greater than
![h(-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k0yg6w3xlehuco4l7z1q8awg8i3cfehm6p.png)
b) is equal than
![h(-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k0yg6w3xlehuco4l7z1q8awg8i3cfehm6p.png)
c) is less than
![h(-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k0yg6w3xlehuco4l7z1q8awg8i3cfehm6p.png)
Since:
![-3<11](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ppzw43pcjj7l42w6p6qw5p8tx90qduumnt.png)
The correct option is:
c) is less than
![h(-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k0yg6w3xlehuco4l7z1q8awg8i3cfehm6p.png)
2. Answer:
From the graph, we can see that when
, then
. From the previous exercise, we know
. So we have:
![g(1)=5 \\ \\ h(-1)=11](https://img.qammunity.org/2020/formulas/mathematics/middle-school/j4hw4eh9248k4083otwszyp5mbzd1h0ybc.png)
For
the options are:
a) is greater than
![h(-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k0yg6w3xlehuco4l7z1q8awg8i3cfehm6p.png)
b) is equal than
![h(-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k0yg6w3xlehuco4l7z1q8awg8i3cfehm6p.png)
c) is less than
![h(-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k0yg6w3xlehuco4l7z1q8awg8i3cfehm6p.png)
Since:
![5<11](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hmms63dc9rdvz83z1ycez8lv6ru2iq55r8.png)
The correct option is:
c) is less than
![h(-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k0yg6w3xlehuco4l7z1q8awg8i3cfehm6p.png)