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x-2(x+1)+3(x-2)+2(x-6)=0

User Mano Kovacs
by
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2 Answers

18 votes
18 votes

Answer:

x = 5

Explanation:

x -2(x+1) + 3(x-2) + 2(x-6) = 0

here, we need to distribute the numbers on the outside of the parentheses to the inside numbers.

As you may know, when two numbers are in parentheses, they are to be multiplied--and it is the same idea here.

When we have a number, say 3, multiplied by parentheses, say (x - 2), we multiply all inside numbers by the outside number, which is called distributing.

We know that 3(x) = 3x, and that 3(-2) = -6, so we distribute

3(x - 2) to be 3x - 6

let's do that for all of our parentheses:
x -2(x+1) + 3(x-2) + 2(x-6) = 0

-2( x + 1 )

-2x - 2

3(x - 2)

3x - 6

2( x - 6)

2x - 12

Now, let's rewrite our problem:

x -2(x+1) + 3(x-2) + 2(x-6) = 0

x - 2x - 2 + 3x -6 + 2x - 12 = 0

First, we should combine like terms:

x - 2x + 3x + 2x - 2 - 6 - 12 = 0

(x - 2x = -x; -x + 3x = 2x; 2x + 2x = 4x)

( - 2 - 6 = -8; -8 - 12 = -20

So, we are left with:

4x - 20 = 0

At this point, we want to get x alone (so that we can find what "x" is)

4x - 20 = 0

+ 20 + 20 ( add 20 to both sides of the equation to isolate x )

4x = 20

÷ 4 ÷ 4 (divide both sides by 4 to find "1"x)

x = 5

So, we know that the value of x is 5, or x = 5

hope this helps! let me know if you need clarification on anything :)

User Ron Savage
by
3.4k points
15 votes
15 votes

Answer:

x = 5

Explanation:

Simplifying the expression:

x - 2(x +1) + 3(x -2) + 2(x - 6) = 0

x + (-2)*x + (-2)*1 + 3*x +3*(-2) + 2*x + 2*(-6) = 0

x - 2x -2 + 3x - 6 + 2x - 12 = 0

x - 2x + 3x + 2x - 2 - 6 - 12 = 0

Combine like terms. Like terms have same variable with same power.

4x - 20 = 0

Add 20 to both sides.

4x = 20

Divide both sides by 4

x = 20/4

x = 5

User Jwwnz
by
2.5k points