143k views
1 vote
If u(x)=x^5-x^4+x^2 and v(x)=-x^2, which expression is equivalent to (u/v)(x)?

2 Answers

0 votes

Answer:

x^3-x^2+1

Explanation:

u(x)=x^5-x^4+x^2

v(x)=-x^2

(u/v)(x) = (x^5-x^4+x^2) /x^2

= (x^5/x^2) - (x^4 /x^2) +(x^2/x^2)

= x^(5-2) - x ^(4-2)+ x ^(2-2)

=x^3-x^2+1

User Shravan Sharma
by
8.8k points
0 votes

Answer:


(u/v)(x)=-x^(3)+x^(2)-1

Explanation:

The arithmetic operation of the two equations presented in this case can be solved as a division of polynomials.

We can write the problem as:


(u/v)(x)=(u(x))/(v(x)) \\\\(u/v)(x)=(x^5-x^4+x^2)/(-x^2)

We need not to forget the negative in the denominator. Then we can factor the numerator as follows:


(u/v)(x)=((-x^2)(-x^3+x^2-1))/((-x^2))

Now we can easily spot the solution, and get there with the following steps:


(u/v)(x)=((-x^2)/(-x^2)) (-x^3+x^2-1)\\\\(u/v)(x)=(1)(-x^3+x^2-1)

As I said earlier we need to remember that the negative will change the symbols in the equation once we factor the polynomial.

And like that we get to the answer:


(u/v)(x)=-x^(3)+x^(2)-1

User Pradeepb
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories