x = first integer
x+1 = integer right after x
For example, if x = 10, then the next one after that is x+1 = 10+1 = 11. So 10 and 11 are consecutive integers (one follows right after the other)
The sum of those two integers x and x+1 add to x+x+1 = 2x+1
This sum is no more than 209, therefore,
![2x+1 \le 209](https://img.qammunity.org/2020/formulas/mathematics/college/ue0xrnianed0o4z2t0ylt1f5za5de9e72n.png)
![2x+1-1 \le 209-1](https://img.qammunity.org/2020/formulas/mathematics/college/cejcmtord450cjbn9k7h5s2jr7aut3096l.png)
![2x \le 208](https://img.qammunity.org/2020/formulas/mathematics/college/gw81ey7kgnbpzqd638sz1gxg3lvlqba4cj.png)
![(2x)/(2) \le (208)/(2)](https://img.qammunity.org/2020/formulas/mathematics/college/esk1x27dcpkcha51gwyj1ozwiz6xxp96h7.png)
![x \le 104](https://img.qammunity.org/2020/formulas/mathematics/college/ydumoof7b968dc0type32bewu1jlm018ix.png)
Therefore the largest x can be is 104
If x = 104, then x+1 = 104+1 = 105
Final Answer: 105
Note how 104+105 = 209, which helps confirm the answer