Question

A balloon contains 2.0 L of air at 101.5 kPa. You squeeze the balloon to a volume of .75 L. What is the pressure of air on the inside of the balloon?

Answer 1

You would use the formula for Boyle's Law:

(P1) (V1) = (P2) (V2)

(101.5) (2.0) = (P2?) (.75)

*P2 = 270kPa (You're allowed 2 significant figures)

P = Pressure

V = Volume

Answer 2

The answer is: P2 = 271kPa

Step-by-step explanation:

Hello!

Let's solve this!

The data we have are:

P1: 101.5kPa

V1: 2L

V2: 0.75L

Q2 :?

P is pressure and V is volume.

In this case, we know that:

P1 * V1 = P2 * V2

We will clear P2 which is what we need to know:

P2 = P1 * V1 / * V2

P2 = (101.5kPa * 2L) /0.75L

P2 = 271kPa

We conclude that the answer is: P2 = 271kPa