Step-by-step explanation:
It is given that, a car moves 30 mi/h to the north. Every second, the velocity increases by 3 mi/h. We know that the rate of change of velocity is called the acceleration of an object.
Here, the velocity increases at the rate of 3 mi/h. It shows the rate of change of velocity i.e. acceleration.
Since,
![a=(dv)/(dt)](https://img.qammunity.org/2020/formulas/chemistry/middle-school/eodhkjmav1bldmwlj2h1r6qyk06m6ut7kh.png)
![a=(3\ mi/h)/(s)](https://img.qammunity.org/2020/formulas/chemistry/middle-school/v99c0owgfvjcee14ysxpy9l7esqyaxcpga.png)
a = 3 mi/h/s
The direction of acceleration is as same as velocity i.e. in north direction. So, the correct option is (d) " 3 mi/h/s north ".