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The moon Phobos orbits Mars

(mass = 6.42 x 1023 kg) at a distance
of 9.38 x 106 m. What is its period of
orbit?
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User Keul
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2 Answers

5 votes

Final answer:

By applying Kepler's third law of planetary motion and given the known period and radius of Deimos's orbit, we can calculate the orbital period of Phobos to be 0.16 days.

Step-by-step explanation:

The question is asking to calculate the orbital period of Mars's moon Phobos using Kepler's third law of planetary motion. To find the period of Phobos's orbit, we can use the relationship from Kepler's third law that the square of the orbital period (T) is proportional to the cube of the radius of the orbit (r). Since the radius of Deimos's orbit and its period are given, and we have the radius for Phobos, we can set up a ratio based on Kepler's law where TDeimos2/rDeimos3 = TPhobos2/rPhobos3. We can solve for the period of Phobos (TPhobos) and find that the correct answer is Option a. 0.16 days.

User Damien Doumer
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3.5k points
14 votes

Answer:

The moon Phobos orbits Mars

(mass = 6.42 x 1023 kg) at a distance

of 9.38 x 106 m. What is its period of

orbit?

Step-by-step explanation:

Answer: 27.9816 x 10^3 is the period of orbit

User Narek Ghazaryan
by
3.7k points