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Find the total surface area of this square based pyramid

Find the total surface area of this square based pyramid-example-1
User Dominic P
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1 Answer

4 votes

Given:

Length of a side of base of a square base pyramid = 6 cm

Height of each triangular surface = 4 cm.

To find:

The total surface area of the square based pyramid.

Solution:

Area of a square with side length a is


\text{Area of square}=a^2

Area of square with side length 6 cm is


\text{Area of square}=(6)^2


\text{Area of square}=36

So, area of square with side length 6 cm is 36 cm².

Area of triangle is


\text{Area of a triangle}=(1)/(2)* base* height

Area of each triangular surface is


\text{Area of each triangular surface}=(1)/(2)* (6)* (4)


\text{Area of each triangular surface}=12

Total area of 4 triangular surfaces is


\text{Area of 4 triangular surfaces}=4* 12


\text{Area of 4 triangular surfaces}=48

So, area of all triangular surfaces is 48 cm².

Now, total area of pyramid is the sum of base area and area of all triangular sides.


Area=36+48


Area=84

Therefore, the area of given square pyramid is 84 cm².

User NIVESH SENGAR
by
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