A hockey puck is at rest on a flat surface. Then one end of the surface is lifted gradually, forming an inclined plane of increasing slope. By measuring the angle of the slope a…

Question

asked Oct 26, 2020 118k views

2 Answers

Lidor Eliyahu Shelef · Answer 1 · 2020-10-28T17:04:48+0000

The coefficient of static friction between the puck and the surface.

In fact, that coefficient describes exactly how "hard" it is to cause the puck to start moving, if it starts from an idle condition.

Keepthepeach · Answer 2 · 2020-10-30T10:46:28+0000

Answer:

the coefficient of static friction between the puck and the surface

Step-by-step explanation:

As per the FBD we can say that as we increase the angle of the inclination the component of force of gravity will counterbalance the friction force

At the condition of just equilibrium when it is just begin to slide then in that case we can say

$F_f = mg sin\theta$

so here for finding frictional force maximum value we can say

$F_f = \mu F_n$

here for finding Normal force we can write force balance normal to the inclined plane

$F_n = mgcos\theta$

now from above equations

$\mu (mgcos\theta) = mg sin\theta$

$\mu = tan\theta$

so angle depends on the coefficient of static friction