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The area of Mr. Rogers’ field is 3 ⅓ square miles. If the width of the field is ⅔ of a mile, what is the length?

User DamianFox
by
5.9k points

1 Answer

8 votes

Answer:

Length of Mr. Roger's field = 5 miles

Explanation:

Given that:

Area of Mr. Roger's field =
3(1)/(3)=(10)/(3) square miles

Width of Mr. Roger's field =
(2)/(3) of a mile

Let,

l be the length of Mr. Roger's field

Area of field = Length * Width


(10)/(3)=(2)/(3)l

Multiplying both sides by 3/2


(3)/(2)*(10)/(3)=(2)/(3)l*(3)/(2)\\5 = l\\l = 5

Hence,

Length of Mr. Roger's field = 5 miles

User Berk
by
5.4k points
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