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21 votes
21 votes
We know for a fact that the equation:


|z+z'| \leqslant |z|+|z'|
holds for any 2 complex numbers

I came up with the conclusion that:

|z+z'|=|z|+|z'|only holds when z and z' are pure imaginary or pure real numbers of the SAME sign.
How can i prove this algebraically/geometrically?
Note: Irrelevant answers will be reported



User Tom Whittock
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1 Answer

19 votes
19 votes

They don't need to be pure real or imaginary. Any "mixed" complex number works so long as
z=z'.

Let
z=z'=a+bi. Then


|z+z'| = |2a+2bi| = 2 √(a^2+b^2)


|z| + |z'| = 2|a+bi| = 2 √(a^2+b^2)

so
|z+z'|=|z|+|z'|.

The geometric interpretation is essentially identical.
|z+z'|=2|z| is a complex number twice the distance away from the origin in the complex plane as
z, which is exactly
|z|+|z|.

User Enver Arslan
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2.4k points