The percent yield : 73.5%
Further explanation
Given
Reaction
C+2H₂⇒CH₄
Required
The percent yield
Solution
mol of Carbon(as a limiting reactant) :
![\tt (100)/(12)=8.3](https://img.qammunity.org/2022/formulas/chemistry/high-school/zhh6z0bzxrsmmxya8z7edjy64hzz868ijo.png)
mol CH₄ based on C, and from equation mol ratio C : CH₄, so mol CH₄ = 8.3
Mass of Methane(theoretical yield) :
![\tt mass=mol* MW\\\\mass=8.3* 16=133.3~g](https://img.qammunity.org/2022/formulas/chemistry/high-school/lxn63misci853p2ier9rnrh0zpid4vtngy.png)
![\tt \%~yield=(actual)/(theoretical)* 100\%\\\\\%yield=(98)/(133.3)* 100\%=73.5\%](https://img.qammunity.org/2022/formulas/chemistry/high-school/95en20eqxh76gq3462qxf0fdrd0ik4s7yo.png)