Question

Using the quadratic formula to solve can 5x=6x²-3, what are the values of x​

Answer 1

The values of x are

`x1=(5(+)√(97))/(12)`

`x2=(5(-)√(97))/(12)`

Explanation:

we know that

The formula to solve a quadratic equation of the form
`ax^(2) +bx+c=0` is equal to

`x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`6x^(2) -5x-3=0`

so

`a=6\\b=-5\\c=-3`

substitute in the formula

`x=\frac{-(-5)(+/-)\sqrt{(-5)^(2)-4(6)(-3)}}{2(6)}`

`x=(5(+/-)√(97))/(12)`

`x1=(5(+)√(97))/(12)`

`x2=(5(-)√(97))/(12)`