Question

Figure ABCD is a trapezoid find the Value of x

Answer 1

The value of
`x` is 4.

Explanation:

Figure
`ABCD` is a trapezoid, in which
`AD` and
`BC` are parallel sides.

Given that,
`AD= 3x+10` and
`BC=2x`

Now, the length of the median
`= (1)/(2)(AD+BC)` , which is given as
`15.`

So, the equation will be......

`(1)/(2)[(3x+10)+2x]=15\\ \\ (1)/(2)(5x+10)=15\\ \\ 5x+10=2(15)\\ \\ 5x+10=30\\ \\ 5x=30-10\\ \\ 5x=20\\ \\ x=(20)/(5)=4`

So, the value of
`x` is 4.

Answer 2

The value of x is 4

Explanation:

we know that

in this problem

`(1)/(2)(2x+(3x+10))=15`

solve for x

`(1)/(2)(5x+10)=15`

`(5x+10)=30`

`5x=30-10`

`x=20/5=4`