Answer:
2.55 m/s
Step-by-step explanation:
The power output can be rewritten as:
(1)
where
F is the force applied
v is the speed at which the bucket is raised
If we want to raise the bucket at constant speed, we must apply a force equal and opposite to the weight of the bucket, which is equal to the product between its mass (4.00 kg) and the gravitational acceleration (9.8 m/s^2):
![F=mg=(4.00 kg)(9.8 m/s^2)=39.2 N](https://img.qammunity.org/2020/formulas/physics/high-school/ihkcbr9nv3zmam82s9azu2pfy0o3o8o3ie.png)
We know that the power output is P = 100 W, so we can re-arrange eq.(1) to find the speed:
![v=(P)/(F)=(100 W)/(39.2 N)=2.55 m/s](https://img.qammunity.org/2020/formulas/physics/high-school/dvqzy711jglp76f1fzebx9ow6nmd3u3eaw.png)