121k views
5 votes
Ind the area of the complex figure.

Ind the area of the complex figure.-example-1
User Hye
by
5.3k points

2 Answers

5 votes

Answer:

1863 m^2

Explanation:

We break down the complex figure into simpler parts, find the areas of the parts, and then sum up the results.

Deleting the entire 23 m-wide vertical middle part, we end up with a rectangle

31 m high and (69 - 23) m wide: 31 m by 46 m. The area of this rectangle is (31 m)(46 m) = 1426 m^2.

Next, we find the are of that middle part we deleted earlier. Its height is (31 - 12) m and its width is 23 m. Thus, this area is 19 m by 23 m, or 437 m^2.

The total area of the figure is (1426 + 437) m^2, or 1863 m^2.

User Wzab
by
5.4k points
0 votes

Answer:

1863 m²

Explanation:

Multiply 69 by 31

69 • 31 = 2139

Multiply 23 by 12

23 • 12 = 276

Subtract 276 from 2139

2139 - 276 = 1863

Answer is 1863 m²

User Mayrop
by
4.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.