182k views
5 votes
Help ppppppppppppllllllllllllllllsssssssss

Help ppppppppppppllllllllllllllllsssssssss-example-1
User Webblover
by
8.0k points

2 Answers

1 vote

david's procedure is correct becsuse Keisha didnt put the correct value of sin theta in equation, she forgot to mention negative sign. though solution are same but in other case it could have gone wrong

User Benjamin Smith Max
by
8.0k points
4 votes

Answer 1:

Option C - Both procedures are correct.

Explanation:

As for Keisha's method of solving the question

  • Tan^2 Q + 1 = Sec^2Q
  • Sin^2 Q/ Cos^2 Q +1 = 1 / Cos^2 Q
  • (8/17)^2 / Cos^2 Q + 1 / Cos ^2 Q
  • Cos Q = +- Square root of 1 - 64/289
  • Cos Q = +- 15/17

Therefore, Keisha's procedure is correct

Answer 2:

Option C - Both procedures are correct.

Explanation:

As for David's method of solving the question.

  • Sin^2 Q + Cos^2 Q = 1
  • Cos^2 Q = 1 - (-8/17)^2
  • Cos Q = +- Square Root of 225/289
  • Cos Q = +- 15/17

Therefore David's procedure is correct.

User Bitmask
by
8.2k points

Related questions

asked Nov 6, 2020 202k views
Marc Sloth Eastman asked Nov 6, 2020
by Marc Sloth Eastman
8.5k points
1 answer
2 votes
202k views
asked Apr 24, 2020 96.1k views
Spyter asked Apr 24, 2020
by Spyter
8.1k points
2 answers
0 votes
96.1k views
asked Feb 4, 2020 42.7k views
Andryuha asked Feb 4, 2020
by Andryuha
8.2k points
2 answers
3 votes
42.7k views