Question

Solve for x. −ax + 4b > 9 plz help me

Answer 1

`\bold{Answer}`

`\boxed{\bold{x<(-9+4b)/(a);\quad \:a\\e \:0}}`

`\bold{Explanation}`

• 
  `\bold{Solve: \ -ax+4b>9}`

`\bold{---------------------}`

• 
  `\bold{Subtract \ 4b \ From \ Both \ Sides}`

`\bold{-ax+4b-4b>9-4b}`

• 
  `\bold{Simplify}`

`\bold{-ax>9-4b}`

• 
  `\bold{Multiply \ Both \ Sides \ By \ -1 \ (Reverse \ Inequality)}`

`\bold{\left(-ax\right)\left(-1\right)<9\left(-1\right)-4b\left(-1\right)}`

• 
  `\bold{Simplify}`

`\bold{ax<-9+4b}`

• 
  `\bold{Divide \ Both \ Sides \ By \ a;\quad \:a\\e \:0}`

`\bold{(ax)/(a)<-(9)/(a)+(4b)/(a);\quad \:a\\e \:0}`

• 
  `\bold{Simplify}`

`\bold{x<(-9+4b)/(a);\quad \:a\\e \:0}`

`\boxed{\bold{Eclipsed}}`

Answer 2

x <
`(9-4b)/(a)`

Explanation:

Given

- ax + 4b > 9 ( isolate the term in x by subtracting 4b from both sides )

- ax > 9 - 4b ( divide both sides by - a )

Remembering to reverse the inequality symbol when dividing by a negative quantity, thus

x <
`(9-4b)/(a)`