Question

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A total of 20.0 mL of sodium hydroxide (NaOH) was neutralized by 30.0 mL of 0.250 M hydrogen bromide (HBr). What was the concentration of the sodium hydroxide?


I also need to know the Solution, Molar Ratio, Volume, and Concentration

Answer 1

The concentration of the sodium hydroxide solution neutralized by hydrogen bromide was 0.375 M, calculated using the volumes and molarities given for the titration and realizing the molar ratio of 1:1 between NaOH and HBr.

Step-by-step explanation:

To find the concentration of sodium hydroxide (NaOH) that was neutralized by hydrogen bromide (HBr), we first need to write down the balanced chemical equation for the reaction:

NaOH (aq) + HBr (aq) → NaBr (aq) + H₂O (l)

From the equation, we see that the molar ratio is 1:1 between NaOH and HBr. To find the moles of HBr that reacted, we use its concentration and volume:

Moles of HBr = molarity (M) × volume (L)
= 0.250 M × 0.030 L
= 0.0075 moles

Since the molar ratio between HBr and NaOH is 1:1, moles of NaOH will also be 0.0075. Now, we can find out the concentration of NaOH using its volume and the number of moles:

Concentration of NaOH = Moles of NaOH / Volume of NaOH (L)
= 0.0075 moles / 0.020 L
= 0.375 M

Therefore, the concentration of the sodium hydroxide solution was 0.375 M.