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1 vote
Question 2 (1 point)

What is an equation of the line that is perpendicular to y=3x−9

and that passes through the point (3, 1) ?
Question 2 options:


y=3x+2


y=−13x+2



y=13x+2



y=-3x+2
Question 3 (1 point)


Select the following lines that would be perpendicular to y = 3x + 1. (Select ALL correct)
Question 3 options:


The line passing through points (3,8) and (6,9).


The line passing through points (1,4) and (4,3).


The line passing through points (1,-4) and (4,-5).


The line passing through points (4,3) and (5,6).

2 Answers

4 votes

Answer: -1/3x + 2

(1,4) and (4.3)

1 vote

♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

Perpendicular ==> negative reciprocal slope

1 = (-1/3)(3) + c

1 = -1 + c

c = 2

It would be y = -1/3x + 2

Q3) slope = difference in y / difference in x

Eq 1 slope: 1/3

Eq 2 slope: -1/3

Eq 3 slope: 1/3

Eq 4 slope: 3/1

It would be The line passing through points (1,4) and (4.3)

A line is perpendicular if it has the negative reciprocal slope

Hope This Helps You!

Good Luck (:

Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ

User Joseph Thomson
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