Question

Write the equation of the line that has an x-intercept of -3 and passes through the point (-3, 7).

Answer 1

The equation would be y = -10/3x - 3

Explanation:

To find this, we start with the slope-intercept form.

y = mx + b

We can input the y intercept for b and the point at (x, y). Then solve for the slope.

y = mx + b

7 = m(-3) + -3

10 = m(-3)

-10/3 = m

Answer 2

x = -3

Explanation:

Since, the line has x-intercept of -3,

⇒ line passes through (-3, 0),

We know that,

The Slope of a line passes through
`(x_1, y_1)` and
`(x_2, y_2)` is,

`m=(y_2-y_1)/(x_2-x_1)`

Slope of the line passes through (-3, 0) and (-3, 7),

`m=(7-0)/(-3+3)=\infty`

That is, the line is parallel to y-axis.

Let the equation of the line,

x = a, where, a is any constant,

Since, it is passes through (-3,0),

⇒ -3 = a

Hence, the equation of the line would be,

`x=-3`