Answer:
(5, - 5)
Explanation:
Given the 2 equations
3x + 2y - 5 = 0 → (1)
x = y + 10 → (2)
Substitute x = y + 10 in (1)
3(y + 10) + 2y - 5 = 0 ← distribute and simplify left side
3y + 30 + 2y - 5 = 0
5y + 25 = 0 ( subtract 25 from both sides )
5y = - 25 ( divide both sides by 5 )
y = - 5
Substitute y = - 5 in (2) for corresponding value of x
x = - 5 + 10 = 5
Solution is (5, - 5)