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from a window 24 feet above the ground, the angle of elevation to the top of another building is 38 degrees. The distance between the buildings 63 feet. Find the height of the building to the nearest tenth of a foot.

User Laverick
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1 Answer

1 vote

Answer:

The height of the building is
73.2\ ft

Explanation:

see the attached figure to better understand the problem

we know that

In the right triangle ABC


tan(38\°)=(BC)/(AB)

we have


AB=63\ ft

substitute and solve for BC


tan(38\°)=(BC)/(63)


BC=(63)tan(38\°)=49.2\ ft

Find the height of the building

The height of the building (h) is equal to


h=BC+24=49.2+24=73.2\ ft

from a window 24 feet above the ground, the angle of elevation to the top of another-example-1
User Mandisa
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