Answer:
45.3 mm
Explanation:
Use the basic 45-45-90 triangle with side length 1 as the building block here. If the length of one side is 1, then the perimeter is 1 + 1 + 1 + 1, or 4, and the length of the diagonal is √2.
We are told that the length of the diagonal of the given square is 16 m.
Determine the length of one side of this square, using an equation of proportions:
16 x
------ = -------
√2 1
16
Then (√2)x = 16, and x = -----------
√2
The perimeter of the given square (with diagonal 16 mm) is 4 times the side length found above, or:
16 16
4 ---------- = (2)(2) ----------- = (2)(√2)(16) = 32√2 (all measurements in mm)
√2 √2
This perimeter, rounded to the nearest tenth, is 45.3 mm.