Question

What is the mass of 5 moles of curious chloride (CmCl3)​

Answer 1

Step-by-step explanation:

Cm=247

Cl=35.5

1 mol = 247 + 35.5 = 282.5

So the mass of 5 moles of CmCl3 = 5 x 282.5

Which is 1412.5g

g=grams

The mass of 5 moles of CmCl3 is 1412.5 grams

Answer 2

Mass of 5 mole of the compound = 1767.5 g

Step-by-step explanation:

The compound from the question is known as curium chloride .The element curium is an artificial element and it is also a radioactive chemical element with the symbol Cm . The element has an atomic number of 96.

Curium and chlorine combines to form curium(iii)chloride. The mass of 5 moles of curium chloride can be computed when you get the mass of 1 mole of the compound.

Atomic mass of curium = 247 amu

Atomic mass of chlorine = 35.5 amu

Mass of chlorine in the compound = 35.5 × 3 = 106.5 g

The mass of 1 mole of the compound(CmCl3) = 106.5 + 247 = 353.5 g

Mass of 5 mole of the compound(CmCl3) = 5 × 353.5

Mass of 5 mole of the compound = 1767.5 g