Question

Write the ratios for sin A and cos A. The triangle is not drawn to scale

Answer 1

`sin(A)=(48)/(50)`,
`cos(A)=(14)/(50)`

Explanation:

Part a) Find the sin(A)

we know that

In the right triangle ABC

`sin(A)=(BC)/(AB)` ----> the sine of angle (A) is the opposite side angle (A) divided by the hypotenuse

substitute the values

`sin(A)=(48)/(50)`

Part b) Find the cos(A)

we know that

In the right triangle ABC

`cos(A)=(AC)/(AB)` ----> the cosine of angle (A) is the adjacent side angle (A) divided by the hypotenuse

substitute the values

`cos(A)=(14)/(50)`