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[Thermodynamics]


\: H_2S \: is \: removed \: by \: the \: following \: reaction. \: How \: many \: grams \: of \: H_2S \: are \: needed \: to \: supply \: 450kj \: of \: energy? ∆H_rxn = -670kJ


[Thermodynamics] \: H_2S \: is \: removed \: by \: the \: following \: reaction. \: How-example-1
User Drmaa
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1 Answer

6 votes

Answer:

45.8 g

Step-by-step explanation:

M_r: 34.08

2H₂S + SO₂ ⇌ 3S + 2H₂O ; ΔH°r = -670 kJ

1. Calculate the moles of H₂S

Treat the heat as if it were a product in the equation. Then use the molar ratio (2 mol H₂S/670 kJ) in the usual way.

Moles of H₂S = 450 kJ × 2 mol H₂S/670 kJ = 1.343 mol H₂S

2. Calculate the mass of H₂S

Mass of H₂S = 1.343 mol H₂S × (34.08 g H₂S/1 mol H₂S) = 45.8 g H₂S

You need 45.8 g of H₂S to produce 450 kJ of energy.

User Amit Suroliya
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