Answer:
The length approximately is 62.36 meters tall.
Explanation:
In this figure DF is hypotenuse , DE is perpendicular and FE is base
So we will use TanQ = perpendicular where Q is theta which is 28 here,
Base,
TanQ= DE/ FE, here DE is 33
Tan (28) = 33/FE
0.53 = 33/FE
FE = 33/0.53
FE = 62.26
Building is 62.36 m tall