Question

Find the equation of the line perpendicular to 2x+3y-6=0 and passing through (-1,1)

Answer 1

Answer:
`y-1=(3)/(2)(x+1)`

Explanation:

`2x+3y-6=0\\\\3y=-2x+6\\\\y=-(2)/(3)x+2`

So, the slope of the given line is -2/3, meaning the slope of the line we want to find is 3/2.

Substituting into point-slope form, we get the equation of the line is

`y-1=(3)/(2)(x+1)`