Question

Solve the equation g^2-12g=-36​

Answer 1

Let us begin by writing the given equation:

g² - 12g = - 36

Bringing all the terms to LHS for getting a quadratic equation,

g² - 12g + 36 = 0

Splitting the middle term,

g² - 6g - 6g + 36 = 0

Taking out common factors,

g ( g - 6 ) - 6 ( g - 6 ) = 0

Taking out common factors,

( g - 6 ) ( g - 6 ) = 0

( g - 6 )² = 0

( g - 6 ) = √0

g - 6 = 0

g = 6

Hence, after solving we get, g = 6

Answer 2

`\bold{Answer}`

`\boxed{\bold{G \ = \ 6}}`

`\bold{Explanation}`

• 
  `\bold{Solve: \ g^2-12g=-36}`

`\bold{---------------------}`

• 
  `\bold{Add \ 36 \ To \ Both \ Sides}`

`\bold{g^2-12g+36=-36+36}`

• 
  `\bold{Simplify}`

`\bold{g^2-12g+36=0}`

• 
  `\bold{Solve \ With \ Quadratic \ Formula}`
• 
  `\bold{a=1,\:b=-12,\:c=36:\quad g_(1,\:2)=(-\left(-12\right)\pm √(\left(-12\right)^2-4\cdot \:1\cdot \:36))/(2\cdot \:1)}`

`\bold{\left(-12\right)^2-4\cdot \:1\cdot \:36 \ = \ 0}`

`\bold{g_(1,\:2)=(-\left(-12\right)\pm √(0))/(2\cdot \:1)}`

`\bold{g=(-\left(-12\right))/(2\cdot \:1)}`

• 
  `\bold{Simplify \ (-\left(-12\right))/(2\cdot \:1) \ = \ 6}`

`\bold{g=6}`

`\boxed{\bold{Eclipsed}}`