Question

Thank you in advance for the help !!! :))

Answer 1

`\bigtriangleup ABD \cong\bigtriangleup BCD\Rightarrow (BD)/(7) = (18)/(BD) \Leftrightarrow {BD}^(2) = 126\Leftrightarrow BD = 3 √(14) \\ BC = \sqrt{{BD}^(2) + {CD}^(2) } = \sqrt{ {3 √(14) }^(2) + {7}^(2) } = √(126 + 49 ) = √(175) \approx 13.2 \\ \Rightarrow B. \: 13.2`