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If a polynomial function f(x) has roots 0 ,4, and 3+ 11, what must also be a root of f(x)

User JBentley
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1 Answer

4 votes

Answer:

3-√11

Explanation:

If a polynomal function f(x) has roots 0, 4 and 3+√11, then 3-√11 must be also a root of f(x).

Probably, we are in front of a four degree polynomial. The first two roots were found, and then the last root was found using the quadratic formula, which states that for a polynomial of the time
ax^(2) +bx + c = 0. The roots are given by:


x1 = \frac{-b+\sqrt{b^(2)-4ac } }{2a}


x2 = \frac{-b-\sqrt{b^(2)-4ac } }{2a}

We have that one root is 3+√11, therefore the other one should be 3-√11.

User IanS
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