Question

How many moles of NaNO3 are present in a 44.0 g sample

Answer 1

Molar mass of NaNO3 is 84.9947 g/mol

Moles=given mass/molar mass

So, 44g/84.9947 g/mol=0.52mol.

Blessed!

Answer 2

Answer : The number of moles of
`NaNO_3` present in a given sample are 0.518 moles.

Explanation : Given,

Mass of
`NaNO_3` = 44.0 g

Molar mass of
`NaNO_3` = 84.99 g

Formula used :

`\text{Moles of }NaNO_3=\frac{\text{Mass of }NaNO_3}{\text{Molar mass of }NaNO_3}`

Now put all the given values in this formula, we get:

`\text{Moles of }NaNO_3=(44.0g)/(84.99g.mol)=0.518mole`

Therefore, the number of moles of
`NaNO_3` present in a given sample are 0.518 moles.