Question

Identify AC rounded to the nearest tenth. HELP ASAP!!

Answer 1

AC = 11.7

Explanation:

Use sine:

`sine=(opposite)/(hypotenuse)`

We have

`opposite=8\\hypotenuse=AC\\\alpha=43^o\\\\\sin43^o\approx0.682`

Substitute:

`(8)/(AC)=0.682`

`(8)/(AC)=(682)/(1,000)` cross multiply

`682AC=8,000` divide both sides by 682

`AC=(8,000)/(682)`

`AC\approx11.7`