Question

PLZ HELP WITH THIS QUESTION!

Answer 1

D

Explanation:

Given the quadratic

d = - 16t² + 12t ← subtract d from both sides

- 16t² + 12t - d = 0 ← in standard form

with a = - 16, b = 12, c = - d

Use the quadratic formula to solve for t

t = ( - 12 ±
`√(12^2-(4(-16)(-d)))`) / - 32

= ( - 12 ±
`√(144-64d)`) / - 32

= ( - 12 ±
`√(16(9-4d))`) / - 32

= ( - 12 ± 4
`√(9-4d)`) / - 32

=
`(-12)/(-32)` ±
`(4)/(-32)`
`√(9-4d)`

=
`(3)/(8)` ±
`(1)/(8)`
`√(9-4d)`

=
`(3)/(8)` ±
`(√(9-4d) )/(8)` → D