Question

The equation of the line is 3x+4y=12.Write the equation of a that goes through the point (-6,2) and perpendicular.

Answer 1

y = 4/3 x + 10

Explanation:

The equation of the line is 3x+4y=12

Need to write 3x+4y=12 in slope intercept form to find slope

3x + 4y = 12

4y = -3x + 12

y = -3/4 x + 3

Perpendicular line, slope is opposite and reciprocal so slope is 4/3

Passing hrough the point (-6,2)

y - 2 = 4/3(x + 6)

y - 2 = 4/3 x +8

y = 4/3 x + 10