Answer:
The angle C measures 48.89°.
Explanation:
We use the Sine inverse trigonometric function to solve for C.
In a triangle the ratio of the side opposite to angle C, and the hypotenuse is given by the Sine function:
![sin(C)=(opposite)/(hypotenuse)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k1xrsojy4rvjsw1roh346ynpc3ea59fd62.png)
and for our angle C, the opposite is 55 and the hypotenuse is 73; thus
![sin(C)=(opposite)/(hypotenuse)=(55)/(73)=0.7534](https://img.qammunity.org/2020/formulas/mathematics/middle-school/m11mugki8hols6g5udyo1hjhdq0d4cmwan.png)
Now the inverse sine function gives back the angle C, if the ratio
is known, that is
![\angle C=sin^(-1)((opposite)/(hypotenuse))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hge2205yxdatixfvsf8tqgehicotz656vx.png)
We know that for angle C
![(opposite)/(hypotenuse)=0.7534](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dmfh0bj6v4eweue0s6yj9i6ks8co2tq2v6.png)
therefore
![\angle C=sin^(-1)((opposite)/(hypotenuse))= sin^(-1)(0.7534})=48.89^o.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/q31b0uf6swwxcgnaexgv7ut4hy4q8aopyl.png)
![\boxed{\therefore \angle C=48.89^o.}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kv17z3fgr8acxogee9yitkbf2d2dpgclyr.png)
Note that we did not use an equation when evaluating
that is because there isn't any: you have just got to use a calculator or memorize some values for the inverse sine function.