Question

A 3.1 kg block initially at rest is pulled to the right along a horizontal frictionless surface by a constant horizontal force of 16.6 N. Find the speed after it has moved 3.8m.

Answer 1

We know, acceleration is given by :

a = F/m

a = 16.6/3.1 m/s²

a = 5.35 m/s²

Now, we need to find the speed after it has moved 3.8 m.

By equation of motion :

`v^2 -u^2 = 2as\\\\v=√(2as)\\\\v = √(2* 5.35 * 3.8 )\ m/s\\\\v = 6.38\ m/s`

Therefore, the speed after it has moved 3.8 m is 6.38 m/s.